There are only two exercises here. The first one is an addition to code from previous exercises (Section 3.1.1 specifically). If you have not completed all the exercises for that part, you’ll need to do so, or download the solution file. The tests also rely on
check-eqv? defined as it was in that file, so make sure it exists either in the old file or that you put it the new one. It’s a good idea to keep the old file as-is, with all its tests, so that if it somehow gets altered, it’ll be easier to determine where the error lies.
The second exercise initially seems difficult to test, since it asks for a function that changes its result depending on which order the arguments are evaluated in. In order to test it based on what we know how to do, there are two possible approaches. We’ll learn other ways to change evaluation order later The first is just to change the expression itself, so that
(+ (f 0) (f 1)) is compared with
(+ (f 1) (f 0)). It turns out that the Scheme language does not actually specify a particular order of argument evaluation. That means that while solutions to this exercise will show a difference, there’s no way to know which one is actually ‘right-to-left’ or ‘left-to-right’. The second approach is to use nested
let statements. Each let works to evaluate an ‘argument’ as a variable for the let, and by changing the order of nesting, the order of evaluation is changed. This will give us a guaranteed order, since we are evaluating the arguments prior to the addition statement. By capturing the result of these
let expressions, we can determine if the results are as expected.
Additionally, there’s an ‘optional’ part of the testing for the second exercise. The problem statement doesn’t clarify if the function only needs to work once, or work at any point in time. Adding more conditions makes the exercise considerably more difficult to solve, so it’s fine to ignore them, as they may not be an intended part of the exercise and thus don’t really need to be tested.